Question

solve for x and y given x is not equal to 0 y is not equal to 0. 2/x+2/3y=1/6,3/x+2/y=0. hence find a for which y=ax-4

Answer 1

Answer:

2/x+2/3y=1/6

3/x+2/y=0

LET , 1/X = P , 1/Y = Q

2P+2Q/3 = 1/6

==> 6P+2Q = 3×1/6

==> 6P+2Q = 1/2...(1)

      3P+2Q  = 0...(2)

==> BY ELIMINATION METHOD

==> 3P = 1/2

==> P = 1/6

    PUTTING VALUE OF P IN EQ(2)

==> 3P+2Q = 0

==> 3(1/6) + 2Q = 0

==> 1/2 +2Q = 0

==> 1+4Q/2 = 0

==> 1+4Q = 2

==> 4Q = 1

==> Q = 1/4

SO, P ===>  1/6 = 1/X

  X = 6

AND , Q ===>  1/4 = 1/Y

 ==> Y  = 4

SO, Y = AX-4

==> 4 = A(6)-4

==> 4 = 6A-4

==> 8 = 6A

==> A = 8/6

==> A = 4/3

Answer 2

Step-by-step explanation:

Here -

Value of x is 6 and value of y is -4 such that

a=4/3