Math, asked by birendrabks2020, 8 months ago

solve for x and y if bx-ay= a^²b-ab^2 and ax+by =a^3+b^3​

Answers

Answered by singhprince0457
1

Answer:

b-a

Step-by-step explanation:

Given equations are:

bx+ay=a  

2

+b  

2

 .....(1)

ax−by=0 .....(2)

Now re-arranging both the equation in ax+by+c=0 form:

bx+ay−(a  

2

+b  

2

)=0 ....(3)

ax−by+0=0 .....(4)

From equation (3) and (4) will get

a  

1

​  

=b,b  

1

​  

=a,c  

1

​  

=−(a  

2

+b  

2

)

a  

2

​  

=a,b  

2

​  

=−b,c  

2

​  

=0

Now applying cross multiplication:

b  

1

​  

c  

2

​  

−b  

2

​  

c  

1

​  

 

x

​  

=  

c  

1

​  

a  

2

​  

−c  

2

​  

a  

1

​  

 

y

​  

=  

a  

1

​  

b  

2

​  

−a  

2

​  

b  

1

​  

 

1

​  

 

(b)(0)−(−b)(−a  

2

−b  

2

)

x

​  

=  

(−a  

2

−b  

2

)a−0(b)

y

​  

=  

b(−b)−a(a)

1

​  

 

⇒  

0+b(−a  

2

−b  

2

)

x

​  

=  

(−a  

2

−b  

2

)a−0

y

​  

=  

−a  

2

−b  

2

 

1

​  

 

⇒  

b(−a  

2

−b  

2

)

x

​  

=  

(−a  

2

−b  

2

)a

y

​  

=  

−a  

2

−b  

2

 

1

​  

 

⇒  

b(−a  

2

−b  

2

)

x

​  

=  

−a  

2

−b  

2

 

1

​  

 

⇒x=b

⇒  

(−a  

2

−b  

2

)a

y

​  

=  

−a  

2

−b  

2

 

1

​  

 

⇒y=a

Hence, x−y⇒b−a

Answered by sanjay4031
0

Step-by-step explanation:

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