Question

Solve for x and y in:-
3x-5y-19=0 and -7x+3y+1=0

thanks​

Answer 1

Step-by-step explanation:

let the 3x-5y-19=0 be eqn1

now we wil take -7x+3y+1=0 as equation 2 now we will solve eqation 1

-1(-7x+3y+1)=0

7x-3y-1=0

7x-3y=1

7x-y=1/3

7x-y=3

let the y will be x

now we will put the value of y in equation 1

3x-5(3)=19

3×-15=19

3x=19+15

3×=34

x=34/3

×=14.6

Answer 2

Answer:

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Step-by-step explanation:

3x - 5y - 19 = 0 ------(1)

-7x + 3y + 1 = 0-------(2)

Multiply equation (1) by 3, and equation (2) by 5,

9x- 15y- 57 = 0------(3)

-35x + 15y +5 = 0-------(4)

Adding both equations (3) and (4),

9x - 15y - 57 = 0

-35x +15y +5 = 0

--------------------------------

-26x - 52 = 0

so, x = -2

Putting value of x in equation (1)

-6 - 5y = 19

-5y = 25

y = -5

Therefore, values of x and y are -2 and -5 respectively.