Math, asked by atul23415, 9 months ago

Solve for x and y in the following given question​

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Answers

Answered by arjun8734
1

Answer:

x = 13 and y = 7

Step-by-step explanation:

Given equation (i)

(x + 1)/2 + (y - 1)/3 = 9

=> 3(x + 1) + 2(y - 1) = 54

=> 3x + 3 + 2y -2 = 54

=> 3x + 2y = 54 - 1

=> 3x + 2y = 53..........(i)

And,

(x - 1)/3 + (y + 1)/2 = 8

=> 2(x - 1) + 3(y + 1) = 48

=> 2x - 2 + 3y + 3 = 48

=> 2x +3y +1 = 48

=> 2x +3y = 48 - 1

=> 2x +3y = 47............(ii)

Now, multiply eq (i) by 3

=> 3(3x + 2y = 53)

=> 9x + 6y = 159

And multiply eq (ii) by 2

=> 2(2x +3y = 47)

=> 4x + 6y = 94

Now subtract eq (ii) from (i)

=> (9x + 6y) - (4x + 6y ) = 159 - 94

=> 9x + 6y - 4x - 6y ) = 65

=> 5x = 65

=> x = 65/5

=> x = 13

Now substitute the value of x in eq (ii),

=> 2x +3y = 47

=> 2(13) + 3y = 47

=> 26 + 3y = 47

=> 3y = 47 - 26

=> 3y = 21

=> y = 21/3

=> y = 7

Therefore, x = 13 and y = 7.

Answered by SeshankMannuru
0

Step-by-step explanation:

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