Solve for x and y in the following given question
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1
Answer:
x = 13 and y = 7
Step-by-step explanation:
Given equation (i)
(x + 1)/2 + (y - 1)/3 = 9
=> 3(x + 1) + 2(y - 1) = 54
=> 3x + 3 + 2y -2 = 54
=> 3x + 2y = 54 - 1
=> 3x + 2y = 53..........(i)
And,
(x - 1)/3 + (y + 1)/2 = 8
=> 2(x - 1) + 3(y + 1) = 48
=> 2x - 2 + 3y + 3 = 48
=> 2x +3y +1 = 48
=> 2x +3y = 48 - 1
=> 2x +3y = 47............(ii)
Now, multiply eq (i) by 3
=> 3(3x + 2y = 53)
=> 9x + 6y = 159
And multiply eq (ii) by 2
=> 2(2x +3y = 47)
=> 4x + 6y = 94
Now subtract eq (ii) from (i)
=> (9x + 6y) - (4x + 6y ) = 159 - 94
=> 9x + 6y - 4x - 6y ) = 65
=> 5x = 65
=> x = 65/5
=> x = 13
Now substitute the value of x in eq (ii),
=> 2x +3y = 47
=> 2(13) + 3y = 47
=> 26 + 3y = 47
=> 3y = 47 - 26
=> 3y = 21
=> y = 21/3
=> y = 7
Therefore, x = 13 and y = 7.
Answered by
0
Step-by-step explanation:
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