solve for x and y
please anyone if u know answer this till now l have not got the perfect answer
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ruhi94:
please help me
Answers
Answered by
4
hola!
log x/ 3 = log y/ 2
log x/ log y = 3/ 2
2log x = 3log y
log x = 3/2 log y
Now,
log (xy) = 5
log x + log y = 5
3/2 log y + log y = 5
log y (5/2) = 5
log y = 5 × 2/5
log y = 2
log y= log 100
→ y = 100.
We know that, log x = 3/2 log y
log x=3/2 × 2
log x = 3
log x = log 1000
→ x = 1000
Hence, The required answer is:-
x = 1000 n' y = 100
hope it helps! :)
log x/ 3 = log y/ 2
log x/ log y = 3/ 2
2log x = 3log y
log x = 3/2 log y
Now,
log (xy) = 5
log x + log y = 5
3/2 log y + log y = 5
log y (5/2) = 5
log y = 5 × 2/5
log y = 2
log y= log 100
→ y = 100.
We know that, log x = 3/2 log y
log x=3/2 × 2
log x = 3
log x = log 1000
→ x = 1000
Hence, The required answer is:-
x = 1000 n' y = 100
hope it helps! :)
Answered by
3
Hi friend!!
Here is your Answer
Here given that
logx/3 = logy/2. and log (xy) =5
so
logx/logy = 3/2
⇒ log y = (2log x )/3 ........... (i) equation
log(xy) = 5
⇒log x + log y = 5 ......( ii) equation
let log x = a
putting the value of log y , use equation (I)
a + 2a/3 = 5
⇒ 3a + 2a = 15
⇒ a = 3
so log x = 3 ⇒ x = 10³
so x = 1000
log y = 2 log X /3
log y = 2
y = 100 Ans
Hope it's helpful ✌✌
Here is your Answer
Here given that
logx/3 = logy/2. and log (xy) =5
so
logx/logy = 3/2
⇒ log y = (2log x )/3 ........... (i) equation
log(xy) = 5
⇒log x + log y = 5 ......( ii) equation
let log x = a
putting the value of log y , use equation (I)
a + 2a/3 = 5
⇒ 3a + 2a = 15
⇒ a = 3
so log x = 3 ⇒ x = 10³
so x = 1000
log y = 2 log X /3
log y = 2
y = 100 Ans
Hope it's helpful ✌✌
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