Question

solve for x and y
$2 \sqrt{x} + 3 \sqrt{y} = 2 and \: 4 \sqrt{x} - 9 \sqrt{y} = - 4$
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Answer 1

HEY MATE HERE'S YOUR ANSWER.....;

$eq {}^{n} (1.) = > 2 \sqrt{x } + 3 \sqrt{y} = 2$

BY SQUARING BOTH SIDE WE GET ,

$4x + 9y = 4$

multiple by 4

16x+36y = 16 ----(3.)

$eq {}^{n} (2.) = > 4 \sqrt{x } - 9 \sqrt{y} = 4$

BY SQUARING BOTH SIDE WE GET ,

$16x + 81y = 16$

SUBTRACT 2-3 WE GET,

$45x = 0$

$x = 0$

PUT VALUE IN 2. WE GET

$81y = 16$

$y = \frac{16}{81}$

HOPE IT'S HELPFUL.....:-)