Math, asked by anony09, 5 months ago

Solve for x and y :
$\frac{8}{2x-3y}+\frac{21}{2x+3y}=11\\\\\frac{5}{2x-3y}+\frac{7}{2x+3y}=6$ , [(2x-3y≠0),(2x+3y≠0)]

Answers

Answered by devarora999

5

Step-by-step explanation:

THE VALUE OF x = 2, y = 1

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