Question

solve for x and y
$x + y = 3 \\ 4x - 3y = 26$
​

Answer 1

Given:

x + y = 3

4x - 3y = 26

To find:

x and y

Solution:

We have

x + y = 3

=> x = 3 - y ----(1)

Now we will substitute the value of x from first equation in the second equation.

$\implies \: 4(3 - y) - 3y = 26 \\ \\ \implies \: 12 - 4y - 3y = 26 \\ \\ \implies \: 12 - 7y = 26 \\ \\ \implies \: - 7y = 26 - 12 \\ \\ \implies \: - 7y = 14 \\ \\ \implies \: y = \frac{14}{ - 7} \\ \\ \implies \: y = - 2$

Now substituting value of y in (1)

$we \: have \\ \implies \: x = 3 - y \\ we \: get \\ = > x = 3 - ( - 2) \\ = > x = 3 + 2 \\ = > x = 5$

Question solved using substitution method

Hence, x = 5 and y = -2

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Answer 2

Given, x + y = 3 => x = 3 - y ----(i)

Now we will substitute the value of x from first equation in the second equation.

4(3−y)−3y=26 ⟹12−4y−3y=26 ⟹12−7y=26 ⟹−7y=26−12 ⟹−7y=14 ⟹y=−2

Now substituting value of y in (i), we get :

x=3−(−2) =>x=3+2 =>x=5

So, the solution is : x=5, y=-2