solve for 'x' and 'y'
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mkrishnan:
is it 741 or 768
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Step-by-step explanation:
in your question a+b+√ab=39
a^2+b^2 +a+b = 741
from first equation a and b are positive
suppose a and b are even we get a contraduction 39 be even
also one is even one is odd we cant get 39
suppose a and b are odd we get 741 be even
suppose 768 is given in place of 741
a = 27 b = 3 is answer
x+2 =27 x=25
y+3 = 3 y=0
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