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hey your answer is as follows
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Step-by-step explanation:
now here 1/5x+y/9=5 can be represented as
1/5×1/x+y/9=5
similarly 1/3x+y/2=14 can be represented as
1/3×1/x+y/2=14
so let let 1/x=k
so thus then
k/5+y/9=5
9k+5y/45=5
ie 9k+5y=225 (1)
k/3+y/2=14
so 2k+3y/6=14
ie 2k+3y=84 (2)
so multiplying (1) by 3 and (2) by 5
we get
27k+15y=675 (3)
10k+15y=420 (4)
subtracting (4) from (3)
we get 17k=255
so k=15
substitute value of k in any of four equations
we get
y=18
so resubstititng value of k as 1/x
we get 1/x=k
1/x=15
ie 15x=1
so x=1/15
thus (x,y)=(1/15,18) is solution of above linear equations
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