solve for x and y using cross multiplication 2x-3y+8=0 and 3x+y+1=0
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×=9
y=4
Step-by-step explanation:
2×-3y+8=0 =n(1)
3×+y+1=0 =n(2)
by putting =n(1) in =n(2)
=2×-3y+8-3×+y+1=0
=3×-2×-3y-y+8+1=0
=×-2y+7=0
if ×=1, then the value if y?
=(1) -2y+7=0
=-2y+7=-1
=-2y=-1-7
=-2y=-8
minus is cut both sides then
=2y=8
=y=8÷2
=y=4
if y=1 then value of x?
=×-2(1) +7=0
×-2+7=0
=×-9=0
×=9
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