solve for x and y using substitution method x÷3+y÷4=11 5x÷6-y÷3+7=0
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x/3 + y/4 = 11
=>4x + 3y = 132 -------------(i)
5x/6 - y/3 + 7 = 0
=>5x - 2y + 42 =0
=>2y = 5x + 42
=>y = (5x+42)/2 -------------(ii)
Now let's put the "y" value from equation (ii) to equation (i).
4x + 3(5x+42)/2 = 132
=> 8x + 15x + 126 = 264
=>23x = 138
=>x = 6
Now let's put "x" value from equation (i) to equation (ii).
y = (5×6 + 42)/2
=>y = 36
x=6, y=36
[ Mark as brainliest please, I'm about to level up. :D]
=>4x + 3y = 132 -------------(i)
5x/6 - y/3 + 7 = 0
=>5x - 2y + 42 =0
=>2y = 5x + 42
=>y = (5x+42)/2 -------------(ii)
Now let's put the "y" value from equation (ii) to equation (i).
4x + 3(5x+42)/2 = 132
=> 8x + 15x + 126 = 264
=>23x = 138
=>x = 6
Now let's put "x" value from equation (i) to equation (ii).
y = (5×6 + 42)/2
=>y = 36
x=6, y=36
[ Mark as brainliest please, I'm about to level up. :D]
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