Question

Solve for X and Y where be divided by x is equal to 3 Y is equal to a square + b square x + Y is equal to 2 a b where a b is not equal to zero

Answer 1

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(c2=ab)x2−2(a2−bc)x+(b2−ac)=0

comparing with Ax2+Bx+C=0, we get

 ∴A=(c2−ab),B=−2(a2−bc),C=(b2−ac)

Roots of the quadratic eqn. are equal

⇒D=0

⇒B2−4AC=0

⇒B2−4AC=0

⇒B2=4AC

⇒[−2(a2−bc)2]=4(c2−ab)(b2−ac)

⇒4(a2−bc)2=4(c2−ab)(b2−ac)

⇒a4+b2c2−2a2bc=b2c2−

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