Question

solve for x and y , x-3y-3=0 ,3x-9y-2=0

Answer 1

Hello,

Solution:

$x - 3y = 3 \\ \\ 3x - 9y = 2$
Since here
$\frac{a1}{a2} = \frac{b1}{b2} \\ \\ \frac{1}{3} = \frac{3}{9} \\ \\ \frac{1}{3} = \frac{1}{3}$
a1 ,a2, b1 and b2 are the coefficient of x and y in above equation.

Thus the pair of linear equations does not have any solution,or we can say that equations are inconsistent.

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

Given :-

x - 3y - 3 = 0 ,

3x - 9y - 2 = 0

Solution :-

x - 3y - 3 = 0                  

3x - 9y - 2 =0                  

a1/a2 = 1/3                  

b1/b2 = - 3/-9 = 1/3                    

c1/c2 = - 3/-2 = 3/2                  

a1/a2 = b1/b2 ≠ c1/c2

                 

Therefore, the sets of lines are parallel.

Therefore, they will not intersect each other

Thus, there will not be any solution for these equations.