Solve For x and y:
x/a + y/b=2
ax - by = a^2 -b^2
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by taking lcm in first equation we get
bx + ay = 2ab
ax - by = a^2 - b ^2
multiplying first equation by b and second by a we get
b^2 X + ab y = 2 ab^2
a^2 X - ab y = a^3 - ab ^2
by adding we get
( a^2 + b ^2 ) X = a^3 + ab ^ 2
( a^2 + b ^2 ) X = a( a^2 + b ^2)
X = a
put the value of X in first equation
a/ a + y/ b = 2
y/ b = 1
y = b
bx + ay = 2ab
ax - by = a^2 - b ^2
multiplying first equation by b and second by a we get
b^2 X + ab y = 2 ab^2
a^2 X - ab y = a^3 - ab ^2
by adding we get
( a^2 + b ^2 ) X = a^3 + ab ^ 2
( a^2 + b ^2 ) X = a( a^2 + b ^2)
X = a
put the value of X in first equation
a/ a + y/ b = 2
y/ b = 1
y = b
DeadlyExpert7:
Can you please explain the addifion part with details?
when we add both + ab y and - ab y will cut each other and a^x and b^x will be added and if we take x common we get x( a^2 + b^2)
and other side we have 2ab^2 and a^3 - ab^2 when we add them we get a^3 + ab^2
i hope you get it
Yes i got it! Thanks!
welcome dude
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