Math, asked by deepanshutyagi0784, 9 months ago

Solve for x and y : x/a =y/b , ax + by = a^2+ b^2

Answers

Answered by Brainlybarbiedoll
1
Given

x/a=y/b

=>x/a-y/b=0

=>bx-ay=0 ----------(1)

or

ax+by=a^2+b^2----------(2)

Multiple a in equation (1)

Nd b in equation (2)

abx-a^2y=0

abx+b^2y=a^2b+b^3

(-) (-) (-) (-)

______________________

-y(a^2+b^2)= -b(a^2+b^2)

=> y=b [•-• because (-) (-) cancel Nd (a^2+b^2) also cancelled ]

Putting (y) value in equation (1)

bx-ay=0

=> bx-ab=0

=> b(x-a)=0

=>x-a=0/b=0

=>x-a=0

=> x=a

•°• The value of x=a, y=b
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