solve for x and y y/2+x=4 2y+x/3=5
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Step-by-step explanation:
The given pair of equations are:
x + y/2 = 4 …………(i)
2y + x/3 = 5…………(ii)
From (i) we get,
x + y/2 = 4
⇒ 2x + y = 8 [After taking LCM]
⇒ y = 8 – 2x …..(iv)
From (ii) we get,
x + 6y = 15 …………(iii) [After taking LCM]
Substituting y in (iii),
we get x + 6(8 – 2x) = 15
⇒ x + 48 – 12x = 15
⇒ -11x = 15 – 48
⇒ -11x = -33
⇒ x = 3
Putting x = 3 in (iv),
we get y = 8 – (2 x 3)
∴ y = 8 – 6 = 2
Hence, the solution of the given system of equation are x = 3 and y = 2
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