Question

Solve for x andy:
8x - y = 6
10x + y = 19



plzz give me right answer plzz​

Answer 1

Answer:

$8x - y = 6 - - - - (1)\\ 10x + y = 19 - - - - (2) \\ \: \: using \: \: elimination \: \: method \\ multiply \: \: (1) \: \: by \: \: 10 \\ 10(8x - y) = 10(6) \\ 80x - 10y = 60 - - - - (3) \\ multiply \: \: (2) \: \: by \: \: 8 \\ 8(10x + y) = 8(19) \\ 80x + 8y = 152 - - - - (4)\\ subtract \: \: (3) \: \: from \: \: (4) \\ 80x - 10y = 60 - - - - (3) \\ 80x + 8y = 152 - - - - (4) \\ 18y = 92 \\ y = \frac{92}{18} \\ y = \frac{46}{9} \\ \: \: put \: \: the \: \: value \: \: of \: \: y \: \:in \: \: (1) \\ 8x - \frac{46}{9} = 6 \\ 8x = 6 + \frac{46}{9} \\ 8x = \frac{54 + 46}{9} \\ 8x = \frac{100}{9} \\x = \frac{100}{9 \times 8} \\ x = \frac{25}{9 \times 2} \\ x = \frac{25}{18}$

I hope it will help you

Answer 2

Answer:

Hyy mate

Step-by-step explanation:

Answer:

\begin{gathered}8x - y = 6 - - - - (1)\\ 10x + y = 19 - - - - (2) \\ \: \: using \: \: elimination \: \: method \\ multiply \: \: (1) \: \: by \: \: 10 \\ 10(8x - y) = 10(6) \\ 80x - 10y = 60 - - - - (3) \\ multiply \: \: (2) \: \: by \: \: 8 \\ 8(10x + y) = 8(19) \\ 80x + 8y = 152 - - - - (4)\\ subtract \: \: (3) \: \: from \: \: (4) \\ 80x - 10y = 60 - - - - (3) \\ 80x + 8y = 152 - - - - (4) \\ 18y = 92 \\ y = \frac{92}{18} \\ y = \frac{46}{9} \\ \: \: put \: \: the \: \: value \: \: of \: \: y \: \:in \: \: (1) \\ 8x - \frac{46}{9} = 6 \\ 8x = 6 + \frac{46}{9} \\ 8x = \frac{54 + 46}{9} \\ 8x = \frac{100}{9} \\x = \frac{100}{9 \times 8} \\ x = \frac{25}{9 \times 2} \\ x = \frac{25}{18} \end{gathered}

8x−y=6−−−−(1)

10x+y=19−−−−(2)

usingeliminationmethod

multiply(1)by10

10(8x−y)=10(6)

80x−10y=60−−−−(3)

multiply(2)by8

8(10x+y)=8(19)

80x+8y=152−−−−(4)

subtract(3)from(4)

80x−10y=60−−−−(3)

80x+8y=152−−−−(4)

18y=92

y=

18

92

y=

9

46

putthevalueofyin(1)

8x−

9

46

=6

8x=6+

9

46

8x=

9

54+46

8x=

9

100

x=

9×8

100

x=

9×2

25

x=

18

25

I hope it will help you