Question

solve for x both elemination and substitution method 3x+7y=1 and 5x-4y-14=0

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Answer 1

Answer:

$x=2\frac{8}{47}$

$y=-\frac{37}{47}$

Step-by-step explanation:

3x + 7y = 1 .............. eq(i)

5x - 4y - 14 = 0

=> 5x - 4y = 14 ........eq(ii)

Elimination Method:

Multiplying equation (i) by 4:

12x + 28y = 4 .........eq(iii)

Multiplying equation (i) by 7:

35x - 28y = 98 .......eq(iv)

Adding equation (iii) and equation (iv):

47x = 102

$x=\frac{102}{47}$ $=2\frac{8}{47}$

Putting value of x in equation (i):

7y $=1 - \frac{306}{47}$ $=-\frac{259}{47}$

∴  $y=-\frac{37}{47}$

Substitution Method:

From equation (i):

$y=\frac{1-3x}{7}$  ........... equation (v)

Putting value of y, from equation (v) into equation (ii):

$5x-4.\frac{1-3x}{7} = 14$

=> 35x - 4 + 12x = 14x7

=>47x = 98 + 4 = 102

∴ x = $\frac{102}{47}$ = $2\frac{8}{47}$

Putting value of x into equation (v):

$y = \frac{1 - 3.\frac{102}{47} }{7} = - \frac{259}{329} = - \frac{37}{47}$

Answer 2

Answer:

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