solve for x by completing the square method 4x^2+4bx-(a^2-b^2)=0
Answers
Answered by
3
4x² +4bx -(a² -b²) = 0
4x² +4bx -a² + b² =0
(2x)² + 2.(2x).b + b² -a² =0
(2x + b)² -a² = 0
use formula,
a²-b² = (a -b)(a + b)
{2x + b -a}{2x + b +a} =0
x = (a - b)/2 , - (a + b)/2
this is your answer
4x² +4bx -a² + b² =0
(2x)² + 2.(2x).b + b² -a² =0
(2x + b)² -a² = 0
use formula,
a²-b² = (a -b)(a + b)
{2x + b -a}{2x + b +a} =0
x = (a - b)/2 , - (a + b)/2
this is your answer
Similar questions