Question

solve for x :
d) √2x²+ 7x+5√2 = 0​

Answer 1

$\huge\purple{Answer}$

$\sqrt{2 {x}^{2} } + 7x + 5 \sqrt{2} = 0 \\ \\ = \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0 \\ = x \sqrt{2} (x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ = (x \sqrt{2} + 5)(x + \sqrt{2} ) = 0 \\ \\ \\ = x = - \frac{5}{ \sqrt{2} } , - \sqrt{2} .$

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