Math, asked by dalbeer59, 4 months ago

solve for x :
d) √2x²+ 7x+5√2 = 0​

Answers

Answered by Anonymous
33

\huge\purple{Answer}

 \sqrt{2 {x}^{2} }   + 7x + 5 \sqrt{2}  = 0 \\  \\  =  \sqrt{2}  {x}^{2}  + 2x + 5x + 5 \sqrt{2}  = 0 \\  = x \sqrt{2} (x +  \sqrt{2} ) + 5(x +  \sqrt{2} ) = 0 \\  = (x \sqrt{2}  + 5)(x +  \sqrt{2} ) = 0 \\  \\  \\  = x =  -  \frac{5}{ \sqrt{2} } , -  \sqrt{2} .

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