Question

solve for x :
e). (a+b)² x²+ 8 (a²–b²) x+16 (a–b)² = 0


Sinharay11 please tell me friend what'sthe solution of this question

I found every app but I can't find the answer....​

Answer 1

$\huge\underline\red{Answer}$

(a+b)²x²+8(a²−b²)x+16(a−b)²=0

Method-1:

(a+b)²x²+8(a+b)(a−b)x+(4(a−b))²=0

⟹((a+b)x+4(a−b))²=0

$⟹x = \frac{ - 4(a - b)}{a + b}$

Method-2

Δ=(8(a²−b²))²−64(a+b)²(a−b)²

⟹Δ=64(a+b)²(a−b)²

−64(a+b)²(a−b)²=0

$x = \frac{ - 8( {a}^{2} - {b}^{2} }{ 2(a + b)^{2} } = \frac{ - 4(a - b)}{(a + b)} \\ \\ \\ = \frac{ 4(a - b)}{a + b}$

$\purple{Answered \: \: by \: \: sinharay11 } \:$

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