Math, asked by temitopealao88, 2 days ago

Solve for X given that sin(5X - 28)° = cos(3X - 50)°.

Answers

Answered by STATUZ

Sin (5x – 28)o = cos (3x - 50)o
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relation
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]o
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o3x – 50 = 90 - (5x-28)
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o3x – 50 = 90 - (5x-28)3x – 50 = 90 – 5x + 28
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o3x – 50 = 90 - (5x-28)3x – 50 = 90 – 5x + 283x + 5x = 90 + 28 + 50
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o3x – 50 = 90 - (5x-28)3x – 50 = 90 – 5x + 283x + 5x = 90 + 28 + 508x = 168
Sin (5x – 28)o = cos (3x - 50)oSince by the trigonometry relationSin(5x – 28)o = cos[90 – (5x – 28)]oHence cos(3x – 50)o = cos[90 – (5x – 28)]o3x – 50 = 90 - (5x-28)3x – 50 = 90 – 5x + 283x + 5x = 90 + 28 + 508x = 168x=1688=21∘

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