solve for x i) x^2-2(a^2+b^2) x+(a^2-b^2) ^2=0
Answers
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Step-by-step explanation:
There is nothing to prove if a = 0. For a
=0, we have
a
2
x
2
−3abx+2b
2
=0
→x
2
−
a
3b
x+
a
2
2b
2
=0 →x
2
−2(
2a
3b
)x=
a
2
−2b
2
→x
2
−2(
2a
3b
)x+
4a
2
9b
2
−
a
2
2b
2
→(x−
2a
3b
)
2
=
4a
2
9b
2
−8b
2
→(x−
2a
3b
)
2
=
4a
2
b
2
→x−
2a
3b
=±
2a
b
→x=
2a
3b±b
Therefore, the solution set is {
a
b
,
a
2b
}.
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