solve for 'x' if (1/x+7) -(1/x+4) =5/6
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x−5)(x−7)(x+6)(x+4)=504{(x−5)(x+4)}{(x−7)(x+6)}=504(x2−x−20)(x2−x−42)=504
Put x2−x=t
(t−20)(t−42)=504t2−62t+840=504t2−62t+336=0t2−6t−56t+336=0t(t−6)−56(t−6)=0(t−56)(t−6)=0t=56,6x2−x=t
For t=56
x2−x=56x2−x−56=0x2−8x+7x−56=0x(x−8)+7(x−8)=0(x+7)(x−8)=0x=−7,8
For t=6
x2−x=6x2−x−6=0x2−3x+2x−6=0x(x−3)+2(x−3)=0(x+2)(x−3)=0x=−2,3
so the values of x are −7,8,−3 and 2
I HOPE IT'S HELPFUL FOR YOU
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