Question

solve for x:if 3x(x-2)-2(x-3)=2​

Answer 1

Answer:

3x(x-2) -2(x-3) = 2

3x^2 - 6x- 2x+6 =2

3x^2-8x =2-6

3x^2--8x = -4

3x^2 -8x +4= 0

3x^2 - 6x-2x +4 =0

(3x^2-6x) - (2x+4)=0

3×(x-2 ) - 2(x-2)

(3x-2) (x-2 )

x=2/3 and x=2

here is your answer

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Answer 2

$\implies3 x ( x - 2 ) - 2 ( x - 2 ) = 2$

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3 x ( x - 2 ) - 2 ( x - 2 ) = 2

3x² - 6x - 2x + 6 = 2

3x² - 6x - 2x = 2 - 6

3x² - 8x = - 4

3x ² - 8x - 4 = 0

Now , factorise it ,

3x ² - 8x - 4 = 0

3x² - 6x - 2x + 4 = 0

( 3x² - 6x ) - ( 2x + 4 ) = 0

3 ( x -2 ) - 2 ( x - 2 )

( 3x - 2 ) ( x - 2 )

x = 2/3 and x = 2

Hence, the value of x is 2/3 and 2 .

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Answer 3

$\implies3 x ( x - 2 ) - 2 ( x - 2 ) = 2$

$\huge{ \underline{\boxed{\red{ \color{red}{\textsf {\textbf{so}{\color{blue}{\textbf {\textsf{lu}}{\color{green}{\textbf{\textsf{ti}}}{\color{orange}{\textsf{\textbf{on}}}}}}}}}}}}}$

3 x ( x - 2 ) - 2 ( x - 2 ) = 2

3x² - 6x - 2x + 6 = 2

3x² - 6x - 2x = 2 - 6

3x² - 8x = - 4

3x ² - 8x - 4 = 0

Now , factorise it ,

3x ² - 8x - 4 = 0

3x² - 6x - 2x + 4 = 0

( 3x² - 6x ) - ( 2x + 4 ) = 0

3 ( x -2 ) - 2 ( x - 2 )

( 3x - 2 ) ( x - 2 )

x = 2/3 and x = 2

Hence, the value of x is 2/3 and 2 .

◆━━━━━━━▣✦▣━━━━━━━━◆

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