Question

solve for x if cos(sec^-1x+cosec^-1 2)=0​

Answer 1

Answer:

Cos(Sec^-1x+ Cosec^-1 2) = 0

(Cos×1/Cosx) + (Cos×1/Sinx) = 0

1+ Cotx = 0

Cotx = -1

Cosx/SinX = -1

Cosx = -Sinx

Cosx = Cos (π/2-x)

x = π/2 - x

2x = π/2

x = π/4

Hope it'll help you, thankyou.

and I think in place of 2 there is x