Question

solve for x.if log(x+2)+(logx-2)=2log3+log5.

Answer 1

log(x+2)+log(x-2)=2log3+log5,

log(x+2)+log(x-2)=log3²+log5,

log[(x+2)(x-2)]=log(3²×5),

since logA+logB=log(AB),

log(x²-2²)=log(3².5),

log(x²-4)=log(9×5),

log(x²-4)=log45,

now taking anti-log, We have

(x²-4)=45,

x²=45+4,

x²=49,

then

x=7