Question

Solve for x if x^2-4ax-b+4a^2=0​

Answer 1

Step-by-step explanation:

x = 4a + √(16a²-4*-(b-4a²) / 2

x = 4a + √16a²+4b-16a² / 2

x = 4a + 2√b / 2

x = 2a + √b

Answer 2

Answer:

PLS check the picture for step by step explaination. Hope this helps you