Question

Solve for x if x^2-4ax-b+4a^2=0​

Answer 1

Answer:

$x^{2}$- 4ax- b+4$a^{2}$

⇒ $x^{2}$ - 2.x. 2a + $(2a)^{2}$ - b

⇒ $(x-2a)^2$ - $( \sqrt{b})^2$

⇒ (x-2a-$\sqrt{b}$) (x-2a+$\sqrt{b}$) = 0

i.e x-2a-$\sqrt{b}$ = 0

& x-2a +$\sqrt{b}$ = 0

or x = 2a +$\sqrt{b}$  or x = 2a-$\sqrt{b}$