Solve for x if x^2+ 5x-(a^2+a-6)=0
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Answer : x = - (a + 3) , x = (a - 2)
Step-by-step explanation:
x^2 + 5x - (a^2 + a - 6) = 0
⇒ x^2 + 5x - (a^2 + 3a - 2a - 6) = 0
⇒ x^2 + 5x - a (a+3) - 2(a+3)=0
⇒x^2 + 5x - (a + 3)(a - 2) = 0
⇒ x^2 + (a + 3) - (a - 2) x - (a + 3)(a - 2) = 0
⇒ x^2 + (a + 3) x - (a - 2)x - (a + 3)(a - 2) = 0
⇒ x[x + (a + 3)] - (a - 2)[x + (a + 3)] = 0
⇒ [x + (a +3 )][x - (a - 2)] = 0
⇒ [x + (a + 3)] = 0 , [x - (a - 2)] = 0
⇒ x = - (a + 3) , x = (a - 2)
Anonymous:
Hope this is helpful for u
i could not understand from the 5th step
please help!!
It's simple
Firstly write my solution on a page
got it!
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