Solve for x, if x + 3 |x| + 2 = 0
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x={-1/2,1}
Step-by-step explanation:
given equation x+3|x|+2=0
we have 2 cases in the solution
1) when x> 0 and ii) when x<0
Note:- when x>0 ,|x|=x and when x<0 |x|= -x
now case-i
when x>0
=> x+3x+2=0
4x= -2
x= -2/4
x= -1/2
case-2
when x<0
=> x-3x+2=0
=> -2x+2=0
-2x=-2
x= -2/-2
x= 1
therefore x= {-1/2,1}
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