Question

solve for x if x-q upon p+q = x+q upon p-q​

Answer 1

Step-by-step explanation:

take the LCM on both sides

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pq

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pqpq = x^2 - px - qx + px

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pqpq = x^2 - px - qx + px0 = x^2 - px - qx

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pqpq = x^2 - px - qx + px0 = x^2 - px - qx0 = x ( x - p - q )

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pqpq = x^2 - px - qx + px0 = x^2 - px - qx0 = x ( x - p - q )0 = x - p - q

take the LCM on both sides( xp - p^2 + qx - q^2 )/pq = ( qx - q^2 + xp - q^2 )/ x^2 - px - qx + pqpq = x^2 - px - qx + px0 = x^2 - px - qx0 = x ( x - p - q )0 = x - p - qx= p + q.

Hope it will help you