Question

solve for x if x square + 5 x minus A square + a minus b is equal to zero​

Answer 1

Step-by-step explanation:

${x}^{2} + 5x - {a}^{2} + a - b = 0 \\ \\ here \\ coefficient \: of \: {x}^{2} = 1 \\ coefficient \: of \: x \: = 5 \\ constant \: = {a}^{2} + a - b \\ \\ \: you \: can \: find \: the \: quadratic \: solution \: if \: possible$

$quadratic \: equation \\ a {x}^{2} + bx + c = 0 \\ x1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a}$

we get a solution if

${b}^{2} - 4ac \geqslant 0$