solve for 'x' in :
[3x+2/ 7] + [4(x+1)/5] = 2/3 (2x+1)
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[3x+2/ 7] + [4(x+1)/5] = 2/3 (2x+1)
⇒ (21x+2)/7+(4x+4)/5=(4x+2)/3
⇒ 5 (21x+2)+(4x+4)7=35*(4x+2)/3
⇒ 15(21x+2)+21(4x+4)=(4x+2)*35
⇒ 315x+30+84x+ 84 = 140x+70
⇒ 399x+114=140x+70
⇒ x= - 44/259
⇒ (21x+2)/7+(4x+4)/5=(4x+2)/3
⇒ 5 (21x+2)+(4x+4)7=35*(4x+2)/3
⇒ 15(21x+2)+21(4x+4)=(4x+2)*35
⇒ 315x+30+84x+ 84 = 140x+70
⇒ 399x+114=140x+70
⇒ x= - 44/259
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