Solve for x in each of the following (2x+5)(3x-2)=20
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(2x+5)(3x-2)=20
6x²-4x+15x-10 = 20
6x²+11x -30 =0
on comparing this eq with
standard form of quadratic equation
ax²+bx+c=0
D= b²-4ac
= 11²-4×6×-30
= 121 +720
D= 841
x= -b+-√D/2a
= -11 +- √841 /12
= -11+- 29/12
when +
x= -11+29/12 = 18/12 = 9/6
when -
x= -11-29/12 = -40/12 = 20/6 = 10/3
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