solve for x in quadratic equation 2(x²-1)= x(1-x)
pls answer soon
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Answer:
2(x^2 - 1) = x(1-x)
2x^2 - 2 = x-x^2
2x^2+x^2 - x -2= 0
3x^2 -x -2 =0
3x^2 - 3x + 2x -2=0
3x(x-1) + 2(x-1)=0
(3x+2)(x-1) =0
x= -2/3, 1
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