Question

Solve for x in terms of a and b:
a/(x-b) + b/(x-a) = 2

Answer 1

a/x-b+b/x-a=2 or a(x-a) +b(x-b) /(x-b)(x-a) or ax-a*a+bx-b*b/x*x-ax-bx+ab=2 or ax-a*a+bx-b*b=2x*x-2ax-2bx+2ab or 2x*x-2ax-ax-2bx-bx+a*a+b*b+2ab=0 or 2x*x-x(3a+3b)+(a+b)(a+b)=0
According to shreedaracharya rule
D=b*b-4ac =(3a+3b)square-4*2*(a+b)square =9a*a+9b*+18ab-8a*a-8b*b-16ab=(a+b)(a+b)
RootD=+-(a+b)
So, x=3a+3b+a+b/4 or 3a+3b-a-b/4=2a-b/2 or a-2b/2

Answer 2

Answer:either a+b or a+b/2

Step-by-step explanation:hope this helps