Solve for x (in terms of "a" and "b") :
If anyone knows it's answer
Then pls answer it....!!!!
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Answer:
Here is your answer
a/x-b + b/x-a = 2
a(x-a) + b(x-b) = 2
(x-a)(x-b)
ax - a^2 + bx - b^2 = 2x^2 - 2bx - 2ax + 2ab
2x^2 - 2bx - bx - 2ax -ax +a^2 + b^2 + 2ab =0
2 x^2 - 3bx - 3ax + (a+ b)^2 = 0
2x^2 - 3x(a+b) + (a+b)(a+b) = 0
2x^2 -2x(a+b) -x(a+b) +(a+b)(a+b) = 0
2x[ x - (a+b)] -(a+b)[ x - (a+b)] = 0
[2x -(a+b)] [ x - (a+b) ] = 0
Now,
[2x-(a+b)] = 0
2x = a+b
x= a+b/2✔️
and
[ x - (a+b)] = 0
x = a+b✔️
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