Question

Solve for x in terms of y; y=3cos^-1 2x

Answer 1

Answer:

4π

Step-by-step explanation:

Consider the basic form:

y=cos(θ)

which has an amplitude of 1

(y has a range of [−1,+1])

and

a period of 2π

(cos(0) to cos(2π) forms one recurring cycle)

In 3cos(12x)

the coefficient 3 stretches the range of y to [−3,+3]

so its amplitude is 3

The coefficient 12 of x forces x to have to extend from

0 to 4π to cover the set of argument values from 0 to 2π

so the period of y=3cos(12x) is 4π

Answer 2

just take 3 under y and take cos on both sides