Question

solve for x in the above problem​

Answer 1

Answer:

${2}^{x} + {2}^{3x} = 16 \\ log( {2}^{x} ) + log {2}^{3x} = log(16) \\ x log(2 ) + 3x log(2) = log(16) \\ x log(2) + 3x log(2) = log(16) \\ x( 2 + 3) =(16 ) \\ x(5) = 16 \\ 5x = 16 \\ x = 3.2$