Question

Solve for x in the question above​

Answer 1

Step-by-step explanation:

log3-log2=logx+3/3x-5

log3/2=logx+3/3x-5

3/2=x+3/3x-5

do it

Answer 2

Answer:

Note:

1) log(AB) = logA + logB

2) log(A/B) = logA - logB

Given:

log2 + log(x+3) - log(3x-5) = log3

To find:

The value of x = ?

Solution:

We have;

=> log2 + log(x+3) - log(3x-5) = log3

=> log(x+3) - log(3x-5) = log3 - log2

=> log{(x+3)/(3x-5)} = log(3/2)

=> (x+3)/(3x-5) = 3/2

=> 2(x+3) = 3(3x-5)

=> 2x + 6 = 9x - 15

=> 9x - 2x = 15 + 6

=> 7x = 21

=> x = 21/7

=> x = 3

Hence, the required value of x is 3.