solve for x Ix²-x-6| = x + 2
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Above LHS Equation is given inside the mode
=> |x²-x-6|=x+2
Now , the Equation inside mode is the form of a quadratic equation so, firstly factorise it .
=>|x²-3x+2x-6|= x+2
Concept
When we remove mode symbol there will be two values come plus and minus.
=> x²-3x+2x-6=±(x+2)
- Taking x+2
=> x²-x-6=x+2
=> x²-x-x-6-2
=> x²-2x-8
=>x²-4x+2x-8
=>x(x-4)+2(x-4)
=>(x+2)(x-4)
Makes equal to zero
(x+2)(x-4)=0
x= -2 ,x = 4
- Taking -(x+2)
=> x²-x-6= -x-2
=>x²-x+x-6+2
=>x²-4
makes equal to zero
=>x²-4= 0
=>x²= 4
x= √4
x= ±2
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