Question

Solve for x. ln (2x-3) + ln (x+1) = ln (2x^2+3)

Answer 1

Answer:

No solution

Step-by-step explanation:

ln (2x - 3) + ln (x + 1) = ln (2x² + 3)

=> ln (2x - 3)(x + 1) = ln (2x² + 3)

=> ( 2x - 3 ) ( x + 1 ) = 2x² + 3

=> 2x² + 2x - 3x - 3 = 2x² + 3

=> -x -3 = 3

=> x = -6

But x = -6 makes 2x-3 and x+1 negative and so cannot have the ln function applied to them.

Therefore there is no solution.

Answer 2

Answer:

Step-by-step explanation:

ln (2x-3) + ln (x+1) = ln (2x^2+3)

ln ((2x-3) * (x+1)) = ln (2x^2+3)

cancel ln from both the sides

(2x-3) * (x+1) = 2x^2+3

x = - 6