Question

Solve for x
log (3x+2) + log (3x-2) = 5 log 2​

Answer 1

Answer:

±2

Step-by-step explanation:

Answer 2

Answer:

given: log (3x + 2) + log (3x - 2) = 5 log 2

to find x

=> log [ (3x + 2)(3x - 2) ] = log 2⁵

=> [ log m + log n = log (m×n), n log m = log mⁿ ]

=> log [ (9x² - 4) ] = log 32

=> taking antilog on both sides,

=> 9x² - 4 = 32

=> 9x² = 36

log of a negative number is not defined

hence -2 is not taken as a value of x

=> x² = 36/9 = |4|

=> x² = 4

=> x = + 2