Question

solve for x : log (3x+2)- log (3x-2)=log5

Answer 1

$log(3x + 2) - log(3x - 2) = log(5) \\ log( \frac{3x + 2}{3x - 2} ) = log5 \\ \frac{3x + 2}{3x - 2} = 5 \\ 3x + 2 = 15x - 10 \\ 12 = 12x \\ x = 1$

Answer 2

Answer:

log(3x+2)−log(3x−2)=log(5)

log(

3x−2

3x+2

)=log5

3x−2

3x+2

=5

3x+2=15x−10

12=12x

x=1