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log² + log (x-3) - log (3x-5) = log3
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hey mate
Step-by-step explanation:
here is your answer
log2 + log(X+3) – log(3x–5) = log 3
log [2(X+3)] – log(3x – 5) = log3
log [2x+6/3x–5] = log3
2x+6/3x–5 = 3
2x + 6 = 9x – 15
–7x = –21
X=3
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