Question

Solve for x : log2x + logx2 = 2​

Answer 1

Step-by-step explanation:

$log(2x) + log( {x}^{2} ) = 2 = > log(2) +$

$log(x) + 2 log(x) = 2 = > 3 log(x) =$

$2 - log(2) = 2 - 0.3010 = 1.699 = >$

$3 log(x) = 1.699 = > log(x) = \frac{1.699}{3} =$

$0.566333 = > x = {10}^{0.566333} = > x =$

$3.68411632 = > x = 3.684$

approximately. Hope it helps you.