Question

solve for x: logx + log5 = 2 + log64

Answer 1

$log \: x + log \: 5 = 2 + log \: 64 \\ \\ \\ = > log \: x \: + log \: 5 = 2(1) \: + log \: 64 \\ \\ \\ = > log \: x \: + log \: 5 = 2 \: log \: 10 + log \: 64 \\ \\ \\ = > log \: (x \times 5) = log \: {10}^{2} + \: log \: 64 \\ \\ \\ = > log(5x) \: = log \: (100 \times 64) \\ \\ \\ = > 5x = 100 \times 64 \\ \\ \\ = > x = \frac{100 \times 64}{5} \\ \\ \\ = > x = 20 \times 64 \\ \\ \\ = > x = 1280$

Answer 2

Hey
HERE your answer....
log x + log 5 =2+log64
log 5x = 2+log64
log 5x - log64 = 2
log 5x/64 = 2
5x/64 = e^2
x = e^2×64/5