Question

solve for x . need it fast

Answer 1

1/x + 2/(2x - 3) = 1/(x - 2)
[(2x - 3) + 2x]/[x . (2x - 3)] = 1/(x - 2)
(4x - 3)/(2x² - 3x) = 1/(x - 2)
(4x - 3)(x - 2) = 2x² - 3x
4x² - 8x - 3x + 6 = 2x² - 3x
4x² - 11x + 6 = 2x² - 3x
4x² - 11x + 6 - 2x² + 3x = 0
2x² - 8x + 6 = 0 (divide by 2 for both sides)
x² - 4x + 3 = 0
x² - 3x - x + 3 = 0
x(x - 3) - 1(x - 3) = 0
(x - 3)(x - 1) = 0
x = 1 or x = 3